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In the figure shown the angle made by the light ray with the normal in the medium of refractive index sqrt 2 is{60}^{o}{90}^{o}{30}^{o}None of these

In the figure shown the angle made by the light ray with the normal in the medium of refractive index sqrt 2 is{60}^{o}{90}^{o}{30}^{o}None of these

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$In the figure shown the angle made by the light ray with the normal in the medium of refractive index sqrt 2 is{60}^{o}{90}^{o}{30}^{o}None of these$

Click here:point_up_2:to get an answer to your question :writing_hand:in the figure shown the angle made by the light ray with the normal in
Click here👆to get an answer to your question ✍️ In the figure shown the angle made by the light ray with the normal in the medium of refractive index sqrt 2 is-60-o-90-o-30-o-None of these
Given- -xA0-x3B8-1-45oUsing Snell-apos-s law of refraction - -xA0- -xA0- -xA0- n1-xD7-sin-x3B8-1-n3-xD7-sin-x3B8-3-x2234- -xA0-xA0-1-xD7-sin45o-x221A-2-xD7-sin-x3B8-3OR -xA0- -xA0- sin-x3B8-3-1-x221A-2-xD7-1-x221A-2-12-xA0-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-x27F9-x3B8-3-30o

In the figure shown, the angle made by the light ray with the normal i

2. In the figure shown, the angle made by the light ray with the normal in the medium of refractive index V2 is von = 1 n = V3 ng = V2 nA = 2 (2) 60° (4) None of these 1) 30° (3) 90°

The retracting angle of a prism is 62, and the refractive index of a glass for a yellow light is 1.65. What is the smallest possible angle of incidence of this yellow

Solved As shown in the figure below, a light ray is incident

The critical angle for a medium is `60^(@)` . The refractive index of the medium is

If a ray of light traveling through the air strikes a glass slab at an angle of 30°, what is the angle of refraction if the refractive index of the glass is

When the ray of light strikes a glass slab at 60°, what is the angle of refraction? - Quora

Angle made by light ray with the normal in medium of refractive index sqrt{2} is sin^{-1}sqrt{dfrac{3}{8}}sin^{-1}sqrt{dfrac{3}{6}}sin^{-1}sqrt{dfrac{3}{ 10}}sin^{-1}sqrt{dfrac{3}{4}}

Why is sin only used to calculate the refractive index, why not cos? - Quora

In the figure given below, the angle made by the light ray with the normal in the medium of refractive index √2 is

A light ray from a medium having a refractive index 1.5 incident on another medium at an angle of 30 degrees. If the angle of refraction is 60 degrees, Find the refractive